x^2+12x-70=-8

Solution for x^2+12x-70=-8 equation:

x^2+12x-70=-8

We move all terms to the left:

x^2+12x-70-(-8)=0

We add all the numbers together, and all the variables

x^2+12x-62=0

a = 1; b = 12; c = -62;
Δ = b2-4ac
Δ = 122-4·1·(-62)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-14\sqrt{2}}{2*1}=\frac{-12-14\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+14\sqrt{2}}{2*1}=\frac{-12+14\sqrt{2}}{2}
$